Search a number
-
+
1301311323000 = 2332531322273769
BaseRepresentation
bin10010111011111100001…
…100101111101101111000
311121101220121211120012200
4102323330030233231320
5132310041144314000
62433451505510200
7163005464511453
oct22737414575570
94541817746180
101301311323000
11461979353607
12190252642360
1395936998200
1446dab7b649a
1523cb4100500
hex12efc32fb78

1301311323000 has 576 divisors, whose sum is σ = 4785050181600. Its totient is φ = 318827059200.

The previous prime is 1301311322981. The next prime is 1301311323007. The reversal of 1301311323000 is 3231131031.

It is a happy number.

1301311323000 is a `hidden beast` number, since 1 + 30 + 1 + 311 + 323 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×13013113230002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301311323007) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 345265116 + ... + 345268884.

Almost surely, 21301311323000 is an apocalyptic number.

1301311323000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1301311323000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2392525090800).

1301311323000 is an abundant number, since it is smaller than the sum of its proper divisors (3483738858600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301311323000 is a wasteful number, since it uses less digits than its factorization.

1301311323000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4049 (or 4019 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 1301311323000 its reverse (3231131031), we get a palindrome (1304542454031).

The spelling of 1301311323000 in words is "one trillion, three hundred one billion, three hundred eleven million, three hundred twenty-three thousand".