Base | Representation |
---|---|
bin | 11101100101101010001111… |
… | …010010011001110010001100 |
3 | 122001202102200122120222210110 |
4 | 131211222033102121302030 |
5 | 114024032422203202200 |
6 | 1140433300551440020 |
7 | 36260451332510214 |
oct | 3545521722316214 |
9 | 561672618528713 |
10 | 130131323100300 |
11 | 38511425412185 |
12 | 127183a4986010 |
13 | 577c43c5c22b2 |
14 | 241c56527d244 |
15 | 100a033661b50 |
hex | 765a8f499c8c |
130131323100300 has 36 divisors (see below), whose sum is σ = 376513294837736. Its totient is φ = 34701686160000.
The previous prime is 130131323100293. The next prime is 130131323100323. The reversal of 130131323100300 is 3001323131031.
It is a super-2 number, since 2×1301313231003002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 216885538201 + ... + 216885538800.
Almost surely, 2130131323100300 is an apocalyptic number.
130131323100300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130131323100300 is an abundant number, since it is smaller than the sum of its proper divisors (246381971737436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130131323100300 is a wasteful number, since it uses less digits than its factorization.
130131323100300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433771077018 (or 433771077011 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 130131323100300 its reverse (3001323131031), we get a palindrome (133132646231331).
The spelling of 130131323100300 in words is "one hundred thirty trillion, one hundred thirty-one billion, three hundred twenty-three million, one hundred thousand, three hundred".
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