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13013200157 is a prime number
BaseRepresentation
bin11000001111010010…
…11010110100011101
31020120220122001200012
430013221122310131
5203122334401112
65551142013005
7640323243026
oct140751326435
936526561605
1013013200157
115578680981
122632117165
1312c5044049
148b6403c4d
155126ad022
hex307a5ad1d

13013200157 has 2 divisors, whose sum is σ = 13013200158. Its totient is φ = 13013200156.

The previous prime is 13013200093. The next prime is 13013200159. The reversal of 13013200157 is 75100231031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8322183076 + 4691017081 = 91226^2 + 68491^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013200157 - 26 = 13013200093 is a prime.

It is a super-2 number, since 2×130132001572 (a number of 21 digits) contains 22 as substring.

Together with 13013200159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13013200159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506600078 + 6506600079.

It is an arithmetic number, because the mean of its divisors is an integer number (6506600079).

Almost surely, 213013200157 is an apocalyptic number.

It is an amenable number.

13013200157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013200157 is an equidigital number, since it uses as much as digits as its factorization.

13013200157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 23.

Adding to 13013200157 its reverse (75100231031), we get a palindrome (88113431188).

The spelling of 13013200157 in words is "thirteen billion, thirteen million, two hundred thousand, one hundred fifty-seven".