1301332111111 has 2 divisors, whose sum is σ = 1301332111112. Its totient is φ = 1301332111110.

The previous prime is 1301332111109. The next prime is 1301332111147. The reversal of 1301332111111 is 1111112331031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1301332111111 - 2¹ = 1301332111109 is a prime.

It is a super-2 number, since 2×1301332111111² (a number of 25 digits) contains 22 as substring.

Together with 1301332111109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301332111171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650666055555 + 650666055556.

It is an arithmetic number, because the mean of its divisors is an integer number (650666055556).

Almost surely, 2^{1301332111111} is an apocalyptic number.

1301332111111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301332111111 is an equidigital number, since it uses as much as digits as its factorization.

1301332111111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1301332111111 its reverse (1111112331031), we get a palindrome (2412444442142).

The spelling of 1301332111111 in words is "one trillion, three hundred one billion, three hundred thirty-two million, one hundred eleven thousand, one hundred eleven".