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130134401040134 = 2431513190709769
BaseRepresentation
bin11101100101101101000110…
…101111110011111100000110
3122001202201122011021112111002
4131211231012233303330012
5114024110223131241014
61140434530222413302
736260620525535561
oct3545550657637406
9561681564245432
10130134401040134
1138512764876a07
1212718b03731232
13577c81019527a
14241c777d734d8
15100a16399ddde
hex765b46bf3f06

130134401040134 has 8 divisors (see below), whose sum is σ = 199741173689640. Its totient is φ = 63554009810256.

The previous prime is 130134401040113. The next prime is 130134401040187. The reversal of 130134401040134 is 431040104431031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130134401040097 and 130134401040106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 756595354799 + ... + 756595354970.

It is an arithmetic number, because the mean of its divisors is an integer number (24967646711205).

Almost surely, 2130134401040134 is an apocalyptic number.

130134401040134 is a deficient number, since it is larger than the sum of its proper divisors (69606772649506).

130134401040134 is a wasteful number, since it uses less digits than its factorization.

130134401040134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1513190709814.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 130134401040134 its reverse (431040104431031), we get a palindrome (561174505471165).

The spelling of 130134401040134 in words is "one hundred thirty trillion, one hundred thirty-four billion, four hundred one million, forty thousand, one hundred thirty-four".

Divisors: 1 2 43 86 1513190709769 3026381419538 65067200520067 130134401040134