Base | Representation |
---|---|
bin | 11101100101101101000110… |
… | …101111110011111100000111 |
3 | 122001202201122011021112111010 |
4 | 131211231012233303330013 |
5 | 114024110223131241020 |
6 | 1140434530222413303 |
7 | 36260620525535562 |
oct | 3545550657637407 |
9 | 561681564245433 |
10 | 130134401040135 |
11 | 38512764876a08 |
12 | 12718b03731233 |
13 | 577c81019527b |
14 | 241c777d734d9 |
15 | 100a16399dde0 |
hex | 765b46bf3f07 |
130134401040135 has 32 divisors (see below), whose sum is σ = 215410375615680. Its totient is φ = 67006913792000.
The previous prime is 130134401040113. The next prime is 130134401040187. The reversal of 130134401040135 is 531040104431031.
It is not a de Polignac number, because 130134401040135 - 28 = 130134401039879 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4713426 + ... + 16807295.
It is an arithmetic number, because the mean of its divisors is an integer number (6731574237990).
Almost surely, 2130134401040135 is an apocalyptic number.
130134401040135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130134401040135 is a deficient number, since it is larger than the sum of its proper divisors (85275974575545).
130134401040135 is a wasteful number, since it uses less digits than its factorization.
130134401040135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21534659.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 130134401040135 its reverse (531040104431031), we get a palindrome (661174505471166).
The spelling of 130134401040135 in words is "one hundred thirty trillion, one hundred thirty-four billion, four hundred one million, forty thousand, one hundred thirty-five".
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