1301353334240 has 24 divisors (see below), whose sum is σ = 3074447252520. Its totient is φ = 520541333632.

The previous prime is 1301353334233. The next prime is 1301353334257. The reversal of 1301353334240 is 424333531031.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 1301353334197 and 1301353334206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4066729010 + ... + 4066729329.

It is an arithmetic number, because the mean of its divisors is an integer number (128101968855).

Almost surely, 2^{1301353334240} is an apocalyptic number.

1301353334240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1301353334240 is an abundant number, since it is smaller than the sum of its proper divisors (1773093918280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301353334240 is an equidigital number, since it uses as much as digits as its factorization.

1301353334240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8133458354 (or 8133458346 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 32.

Adding to 1301353334240 its reverse (424333531031), we get a palindrome (1725686865271).

The spelling of 1301353334240 in words is "one trillion, three hundred one billion, three hundred fifty-three million, three hundred thirty-four thousand, two hundred forty".