13014011130032 has 60 divisors (see below), whose sum is σ = 27717253742640. Its totient is φ = 5915036772480.

The previous prime is 13014011130023. The next prime is 13014011130073. The reversal of 13014011130032 is 23003111041031.

It is a super-3 number, since 3×13014011130032³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13014011129986 and 13014011130013.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27689894 + ... + 28155962.

It is an arithmetic number, because the mean of its divisors is an integer number (461954229044).

Almost surely, 2^{13014011130032} is an apocalyptic number.

It is an amenable number.

13014011130032 is an abundant number, since it is smaller than the sum of its proper divisors (14703242612608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13014011130032 is a wasteful number, since it uses less digits than its factorization.

13014011130032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 480522 (or 480505 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13014011130032 its reverse (23003111041031), we get a palindrome (36017122171063).

The spelling of 13014011130032 in words is "thirteen trillion, fourteen billion, eleven million, one hundred thirty thousand, thirty-two".