1301404041031 has 4 divisors (see below), whose sum is σ = 1325958834312. Its totient is φ = 1276849247752.

The previous prime is 1301404041019. The next prime is 1301404041061.

It is a happy number.

1301404041031 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301404041031 - 2⁵ = 1301404040999 is a prime.

It is a super-2 number, since 2×1301404041031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301404040993 and 1301404041011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301404041061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12277396561 + ... + 12277396666.

It is an arithmetic number, because the mean of its divisors is an integer number (331489708578).

Almost surely, 2^{1301404041031} is an apocalyptic number.

1301404041031 is a deficient number, since it is larger than the sum of its proper divisors (24554793281).

1301404041031 is an equidigital number, since it uses as much as digits as its factorization.

1301404041031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24554793280.

The product of its (nonzero) digits is 576, while the sum is 22.

The spelling of 1301404041031 in words is "one trillion, three hundred one billion, four hundred four million, forty-one thousand, thirty-one".