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13014121301 = 17807730843
BaseRepresentation
bin11000001111011001…
…11011101101010101
31020120222100212020122
430013230323231111
5203123103340201
65551213441325
7640334130416
oct140754735525
936528325218
1013014121301
11557914aa55
1226324a0245
1312c52a73bc
148b65a380d
155127e0e1b
hex307b3bb55

13014121301 has 4 divisors (see below), whose sum is σ = 13014869952. Its totient is φ = 13013372652.

The previous prime is 13014121283. The next prime is 13014121321. The reversal of 13014121301 is 10312141031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13014121301 - 226 = 12947012437 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13014121301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13014121321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347615 + ... + 383228.

It is an arithmetic number, because the mean of its divisors is an integer number (3253717488).

Almost surely, 213014121301 is an apocalyptic number.

It is an amenable number.

13014121301 is a deficient number, since it is larger than the sum of its proper divisors (748651).

13014121301 is an equidigital number, since it uses as much as digits as its factorization.

13014121301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 748650.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13014121301 its reverse (10312141031), we get a palindrome (23326262332).

The spelling of 13014121301 in words is "thirteen billion, fourteen million, one hundred twenty-one thousand, three hundred one".

Divisors: 1 17807 730843 13014121301