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130141315335 = 3521141118899
BaseRepresentation
bin111100100110100000…
…1101110000100000111
3110102220202211210211010
41321031001232010013
54113012134042320
6135441444013303
712255010633263
oct1711501560407
9412822753733
10130141315335
115021341a469
1221280091233
13c370252785
1464281730a3
1535ba479ae0
hex1e4d06e107

130141315335 has 16 divisors (see below), whose sum is σ = 209212963200. Its totient is φ = 69079748640.

The previous prime is 130141315333. The next prime is 130141315361. The reversal of 130141315335 is 533513141031.

It is not a de Polignac number, because 130141315335 - 21 = 130141315333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130141315333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20556285 + ... + 20562614.

It is an arithmetic number, because the mean of its divisors is an integer number (13075810200).

Almost surely, 2130141315335 is an apocalyptic number.

130141315335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130141315335 is a deficient number, since it is larger than the sum of its proper divisors (79071647865).

130141315335 is a wasteful number, since it uses less digits than its factorization.

130141315335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41119118.

The product of its (nonzero) digits is 8100, while the sum is 30.

Adding to 130141315335 its reverse (533513141031), we get a palindrome (663654456366).

The spelling of 130141315335 in words is "one hundred thirty billion, one hundred forty-one million, three hundred fifteen thousand, three hundred thirty-five".

Divisors: 1 3 5 15 211 633 1055 3165 41118899 123356697 205594495 616783485 8676087689 26028263067 43380438445 130141315335