Base | Representation |
---|---|
bin | 1011110101101110101101… |
… | …1110000000011101100000 |
3 | 1201002110221222211202221222 |
4 | 2331123223132000131200 |
5 | 3201240223030400343 |
6 | 43404125515234212 |
7 | 2512332530233460 |
oct | 275335336003540 |
9 | 51073858752858 |
10 | 13017701418848 |
11 | 416985a097775 |
12 | 1562b01a48968 |
13 | 735744096959 |
14 | 3300bad2bba0 |
15 | 178948711a68 |
hex | bd6eb780760 |
13017701418848 has 24 divisors (see below), whose sum is σ = 29289828192912. Its totient is φ = 5579014893696.
The previous prime is 13017701418829. The next prime is 13017701418941. The reversal of 13017701418848 is 84881410771031.
It is a self number, because there is not a number n which added to its sum of digits gives 13017701418848.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29057369015 + ... + 29057369462.
It is an arithmetic number, because the mean of its divisors is an integer number (1220409508038).
Almost surely, 213017701418848 is an apocalyptic number.
It is an amenable number.
13017701418848 is an abundant number, since it is smaller than the sum of its proper divisors (16272126774064).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13017701418848 is an equidigital number, since it uses as much as digits as its factorization.
13017701418848 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58114738494 (or 58114738486 counting only the distinct ones).
The product of its (nonzero) digits is 1204224, while the sum is 53.
The spelling of 13017701418848 in words is "thirteen trillion, seventeen billion, seven hundred one million, four hundred eighteen thousand, eight hundred forty-eight".
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