Base | Representation |
---|---|
bin | 11101100110101100011101… |
… | …001111010110000101010001 |
3 | 122002000020012210202001100101 |
4 | 131212230131033112011101 |
5 | 114031214031034440423 |
6 | 1140530100133452401 |
7 | 36265546306413403 |
oct | 3546543517260521 |
9 | 562006183661311 |
10 | 130202424140113 |
11 | 385395a1069806 |
12 | 1272a1284a1101 |
13 | 5786060b929a0 |
14 | 2421b8c1c4b73 |
15 | 100bce57617ad |
hex | 766b1d3d6151 |
130202424140113 has 8 divisors (see below), whose sum is σ = 148466112594408. Its totient is φ = 113117038166784.
The previous prime is 130202424140057. The next prime is 130202424140153. The reversal of 130202424140113 is 311041424202031.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 33351179402304 + 96851244737809 = 5775048^2 + 9841303^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130202424140113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130202424140153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 294575620006 + ... + 294575620447.
It is an arithmetic number, because the mean of its divisors is an integer number (18558264074301).
Almost surely, 2130202424140113 is an apocalyptic number.
130202424140113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
130202424140113 is a deficient number, since it is larger than the sum of its proper divisors (18263688454295).
130202424140113 is a wasteful number, since it uses less digits than its factorization.
130202424140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 589151240483.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 130202424140113 its reverse (311041424202031), we get a palindrome (441243848342144).
The spelling of 130202424140113 in words is "one hundred thirty trillion, two hundred two billion, four hundred twenty-four million, one hundred forty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •