Base | Representation |
---|---|
bin | 10010111100100111010… |
… | …010000011100001110000 |
3 | 11121110202222221020002010 |
4 | 102330213102003201300 |
5 | 132313031214311102 |
6 | 2434051330122520 |
7 | 163032422353512 |
oct | 22744722034160 |
9 | 4543688836063 |
10 | 1302034135152 |
11 | 46220a364023 |
12 | 190414720440 |
13 | 95a206639ca |
14 | 470397abbb2 |
15 | 23d077cbd6c |
hex | 12f27483870 |
1302034135152 has 40 divisors (see below), whose sum is σ = 3366218199040. Its totient is φ = 433672021440.
The previous prime is 1302034135121. The next prime is 1302034135153. The reversal of 1302034135152 is 2515314302031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1302034135153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10542874 + ... + 10665657.
It is an arithmetic number, because the mean of its divisors is an integer number (84155454976).
Almost surely, 21302034135152 is an apocalyptic number.
1302034135152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1302034135152 is an abundant number, since it is smaller than the sum of its proper divisors (2064184063888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1302034135152 is a wasteful number, since it uses less digits than its factorization.
1302034135152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21209821 (or 21209815 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 1302034135152 its reverse (2515314302031), we get a palindrome (3817348437183).
The spelling of 1302034135152 in words is "one trillion, three hundred two billion, thirty-four million, one hundred thirty-five thousand, one hundred fifty-two".
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