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130211202103 = 711993920201
BaseRepresentation
bin111100101000100110…
…0010100010000110111
3110110002122100102102221
41321101030110100313
54113133031431403
6135452421543211
712256516645633
oct1712114242067
9413078312387
10130211202103
1150249913424
122129b574b07
13c3818818a8
146433565dc3
1535c1681dbd
hex1e51314437

130211202103 has 8 divisors (see below), whose sum is σ = 132111560736. Its totient is φ = 128312688000.

The previous prime is 130211202089. The next prime is 130211202169. The reversal of 130211202103 is 301202112031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130211202103 - 25 = 130211202071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130211232103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 318598 + ... + 601603.

It is an arithmetic number, because the mean of its divisors is an integer number (16513945092).

Almost surely, 2130211202103 is an apocalyptic number.

130211202103 is a deficient number, since it is larger than the sum of its proper divisors (1900358633).

130211202103 is an equidigital number, since it uses as much as digits as its factorization.

130211202103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 922265.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 130211202103 its reverse (301202112031), we get a palindrome (431413314134).

The spelling of 130211202103 in words is "one hundred thirty billion, two hundred eleven million, two hundred two thousand, one hundred three".

Divisors: 1 71 1993 141503 920201 65334271 1833960593 130211202103