Base | Representation |
---|---|
bin | 11101100110110101011111… |
… | …001010100111000111101111 |
3 | 122002001011020112110101001002 |
4 | 131212311133022213013233 |
5 | 114031343410223130111 |
6 | 1140534342220310515 |
7 | 36266341503104522 |
oct | 3546653712470757 |
9 | 562034215411032 |
10 | 130212120130031 |
11 | 38542717210515 |
12 | 1272bb936a243b |
13 | 5786c478aa024 |
14 | 242242bc0cbb9 |
15 | 100c1b1abc63b |
hex | 766d5f2a71ef |
130212120130031 has 2 divisors, whose sum is σ = 130212120130032. Its totient is φ = 130212120130030.
The previous prime is 130212120130021. The next prime is 130212120130033. The reversal of 130212120130031 is 130031021212031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (130031021212031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130212120130031 is a prime.
It is a super-2 number, since 2×1302121201300312 (a number of 29 digits) contains 22 as substring.
Together with 130212120130033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 130212120129985 and 130212120130012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130212120130033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106060065015 + 65106060065016.
It is an arithmetic number, because the mean of its divisors is an integer number (65106060065016).
Almost surely, 2130212120130031 is an apocalyptic number.
130212120130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
130212120130031 is an equidigital number, since it uses as much as digits as its factorization.
130212120130031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 130212120130031 its reverse (130031021212031), we get a palindrome (260243141342062).
The spelling of 130212120130031 in words is "one hundred thirty trillion, two hundred twelve billion, one hundred twenty million, one hundred thirty thousand, thirty-one".
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