130213100119 has 2 divisors, whose sum is σ = 130213100120. Its totient is φ = 130213100118.

The previous prime is 130213100113. The next prime is 130213100141. The reversal of 130213100119 is 911001312031.

It is an a-pointer prime, because the next prime (130213100141) can be obtained adding 130213100119 to its sum of digits (22).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130213100119 - 2¹⁵ = 130213067351 is a prime.

It is a super-2 number, since 2×130213100119² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130213100119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130213100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106550059 + 65106550060.

It is an arithmetic number, because the mean of its divisors is an integer number (65106550060).

Almost surely, 2^130213100119 is an apocalyptic number.

130213100119 is a deficient number, since it is larger than the sum of its proper divisors (1).

130213100119 is an equidigital number, since it uses as much as digits as its factorization.

130213100119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 130213100119 in words is "one hundred thirty billion, two hundred thirteen million, one hundred thousand, one hundred nineteen".