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130213100141 is a prime number
BaseRepresentation
bin111100101000101001…
…1100011101001101101
3110110002202220212001122
41321101103203221231
54113134023201031
6135452530350325
712256542042365
oct1712123435155
9413082825048
10130213100141
115024a99a453
12212a012b3a5
13c3820977a7
1464338db9a5
1535c190947b
hex1e514e3a6d

130213100141 has 2 divisors, whose sum is σ = 130213100142. Its totient is φ = 130213100140.

The previous prime is 130213100119. The next prime is 130213100183. The reversal of 130213100141 is 141001312031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69790544041 + 60422556100 = 264179^2 + 245810^2 .

It is a cyclic number.

It is not a de Polignac number, because 130213100141 - 210 = 130213099117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130213150141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106550070 + 65106550071.

It is an arithmetic number, because the mean of its divisors is an integer number (65106550071).

Almost surely, 2130213100141 is an apocalyptic number.

It is an amenable number.

130213100141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130213100141 is an equidigital number, since it uses as much as digits as its factorization.

130213100141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 130213100141 its reverse (141001312031), we get a palindrome (271214412172).

The spelling of 130213100141 in words is "one hundred thirty billion, two hundred thirteen million, one hundred thousand, one hundred forty-one".