Base | Representation |
---|---|
bin | 111100101000110110… |
… | …1111111110010001111 |
3 | 110110010020221222120112 |
4 | 1321101231333302033 |
5 | 4113142311443434 |
6 | 135453335110235 |
7 | 12256655000333 |
oct | 1712155776217 |
9 | 413106858515 |
10 | 130220031119 |
11 | 502538a3832 |
12 | 212a251237b |
13 | c383653469 |
14 | 64347c37c3 |
15 | 35c2327dce |
hex | 1e51b7fc8f |
130220031119 has 2 divisors, whose sum is σ = 130220031120. Its totient is φ = 130220031118.
The previous prime is 130220031101. The next prime is 130220031157. The reversal of 130220031119 is 911130022031.
It is a weak prime.
It is an emirp because it is prime and its reverse (911130022031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130220031119 is a prime.
It is a super-2 number, since 2×1302200311192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130220031094 and 130220031103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130220030119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110015559 + 65110015560.
It is an arithmetic number, because the mean of its divisors is an integer number (65110015560).
Almost surely, 2130220031119 is an apocalyptic number.
130220031119 is a deficient number, since it is larger than the sum of its proper divisors (1).
130220031119 is an equidigital number, since it uses as much as digits as its factorization.
130220031119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 130220031119 in words is "one hundred thirty billion, two hundred twenty million, thirty-one thousand, one hundred nineteen".
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