Base | Representation |
---|---|
bin | 1011110110000001000011… |
… | …0010111001110101001111 |
3 | 1201002221122221221202012121 |
4 | 2331200100302321311033 |
5 | 3201330312342333012 |
6 | 43410302113513411 |
7 | 2512565504612566 |
oct | 275402062716517 |
9 | 51087587852177 |
10 | 13022622621007 |
11 | 4170954a7479a |
12 | 1563a55b72867 |
13 | 7360497c63ac |
14 | 33042675abdd |
15 | 178b357a0a07 |
hex | bd810cb9d4f |
13022622621007 has 2 divisors, whose sum is σ = 13022622621008. Its totient is φ = 13022622621006.
The previous prime is 13022622620977. The next prime is 13022622621037. The reversal of 13022622621007 is 70012622622031.
It is a balanced prime because it is at equal distance from previous prime (13022622620977) and next prime (13022622621037).
It is a cyclic number.
It is not a de Polignac number, because 13022622621007 - 219 = 13022622096719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13022622621037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511311310503 + 6511311310504.
It is an arithmetic number, because the mean of its divisors is an integer number (6511311310504).
Almost surely, 213022622621007 is an apocalyptic number.
13022622621007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022622621007 is an equidigital number, since it uses as much as digits as its factorization.
13022622621007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 13022622621007 in words is "thirteen trillion, twenty-two billion, six hundred twenty-two million, six hundred twenty-one thousand, seven".
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