Base | Representation |
---|---|
bin | 111100101001010000… |
… | …0010110011111001111 |
3 | 110110011011210121211112 |
4 | 1321102200112133033 |
5 | 4113204201400221 |
6 | 135454530042235 |
7 | 12260205126011 |
oct | 1712240263717 |
9 | 413134717745 |
10 | 130233231311 |
11 | 5026029a287 |
12 | 212a6a1937b |
13 | c3862c5821 |
14 | 643645c1b1 |
15 | 35c358415b |
hex | 1e528167cf |
130233231311 has 2 divisors, whose sum is σ = 130233231312. Its totient is φ = 130233231310.
The previous prime is 130233231241. The next prime is 130233231313. The reversal of 130233231311 is 113132332031.
It is a strong prime.
It is an emirp because it is prime and its reverse (113132332031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130233231311 - 210 = 130233230287 is a prime.
Together with 130233231313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130233231313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116615655 + 65116615656.
It is an arithmetic number, because the mean of its divisors is an integer number (65116615656).
Almost surely, 2130233231311 is an apocalyptic number.
130233231311 is a deficient number, since it is larger than the sum of its proper divisors (1).
130233231311 is an equidigital number, since it uses as much as digits as its factorization.
130233231311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 130233231311 its reverse (113132332031), we get a palindrome (243365563342).
The spelling of 130233231311 in words is "one hundred thirty billion, two hundred thirty-three million, two hundred thirty-one thousand, three hundred eleven".
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