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13023641367719 is a prime number
BaseRepresentation
bin1011110110000100110110…
…0001000111010010100111
31201010001021221220102222022
42331201031201013102213
53201334404142231334
643410551145053355
72512632655042613
oct275411541072247
951101257812868
1013023641367719
114171328032224
12156409b18725b
1373617c8983b8
143304c1b88343
15178b94e3682e
hexbd84d8474a7

13023641367719 has 2 divisors, whose sum is σ = 13023641367720. Its totient is φ = 13023641367718.

The previous prime is 13023641367673. The next prime is 13023641367721. The reversal of 13023641367719 is 91776314632031.

It is a happy number.

13023641367719 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13023641367719 - 216 = 13023641302183 is a prime.

It is a super-2 number, since 2×130236413677192 (a number of 27 digits) contains 22 as substring.

Together with 13023641367721, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13023641667719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511820683859 + 6511820683860.

It is an arithmetic number, because the mean of its divisors is an integer number (6511820683860).

Almost surely, 213023641367719 is an apocalyptic number.

13023641367719 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023641367719 is an equidigital number, since it uses as much as digits as its factorization.

13023641367719 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3429216, while the sum is 53.

The spelling of 13023641367719 in words is "thirteen trillion, twenty-three billion, six hundred forty-one million, three hundred sixty-seven thousand, seven hundred nineteen".