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130240104341 is a prime number
BaseRepresentation
bin111100101001011101…
…0100100011110010101
3110110011122201210212012
41321102322210132111
54113212431314331
6135455333234005
712260320423004
oct1712272443625
9413148653765
10130240104341
1150264164076
12212a9192905
13c387860cc9
14643732ac3b
1535c3e9082b
hex1e52ea4795

130240104341 has 2 divisors, whose sum is σ = 130240104342. Its totient is φ = 130240104340.

The previous prime is 130240104307. The next prime is 130240104343. The reversal of 130240104341 is 143401042031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129975391441 + 264712900 = 360521^2 + 16270^2 .

It is a cyclic number.

It is not a de Polignac number, because 130240104341 - 230 = 129166362517 is a prime.

Together with 130240104343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130240104343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65120052170 + 65120052171.

It is an arithmetic number, because the mean of its divisors is an integer number (65120052171).

Almost surely, 2130240104341 is an apocalyptic number.

It is an amenable number.

130240104341 is a deficient number, since it is larger than the sum of its proper divisors (1).

130240104341 is an equidigital number, since it uses as much as digits as its factorization.

130240104341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130240104341 its reverse (143401042031), we get a palindrome (273641146372).

The spelling of 130240104341 in words is "one hundred thirty billion, two hundred forty million, one hundred four thousand, three hundred forty-one".