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130240310200000 = 265571121359141
BaseRepresentation
bin11101100111001111101111…
…011011001100011011000000
3122002010212000011001022011121
4131213033233123030123000
5114032324123402400000
61140555323355322024
736301360204540450
oct3547175733143300
9562125004038147
10130240310200000
1138553672828300
1212735540450314
1357897bacb62c0
142423943b17d60
15100ccb187ab1a
hex7673ef6cc6c0

130240310200000 has 1008 divisors, whose sum is σ = 437020319784384. Its totient is φ = 37471104000000.

The previous prime is 130240310199991. The next prime is 130240310200003. The reversal of 130240310200000 is 2013042031.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (130240310200003) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 2202170430 + ... + 2202229570.

It is an arithmetic number, because the mean of its divisors is an integer number (433551904548).

Almost surely, 2130240310200000 is an apocalyptic number.

130240310200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130240310200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218510159892192).

130240310200000 is an abundant number, since it is smaller than the sum of its proper divisors (306780009584384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130240310200000 is an equidigital number, since it uses as much as digits as its factorization.

130240310200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59220 (or 59179 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 130240310200000 its reverse (2013042031), we get a palindrome (130242323242031).

The spelling of 130240310200000 in words is "one hundred thirty trillion, two hundred forty billion, three hundred ten million, two hundred thousand".