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130243421213112 = 2335426809217213
BaseRepresentation
bin11101100111010010101000…
…110110110001000110111000
3122002011011000221222010212110
4131213102220312301012320
5114032402011312304422
61141001000211212320
736301530251654514
oct3547225066610670
9562134027863773
10130243421213112
1138554a19921519
121273606a2a70a0
135789b9569906c
142423b5ad7b144
15100cde4a4c60c
hex7674a8db11b8

130243421213112 has 16 divisors (see below), whose sum is σ = 325608553032840. Its totient is φ = 43414473737696.

The previous prime is 130243421213111. The next prime is 130243421213119. The reversal of 130243421213112 is 211312124342031.

130243421213112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1302434212131122 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130243421213112.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130243421213111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2713404608583 + ... + 2713404608630.

Almost surely, 2130243421213112 is an apocalyptic number.

130243421213112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130243421213112 is an abundant number, since it is smaller than the sum of its proper divisors (195365131819728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130243421213112 is a wasteful number, since it uses less digits than its factorization.

130243421213112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5426809217222 (or 5426809217218 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 130243421213112 its reverse (211312124342031), we get a palindrome (341555545555143).

The spelling of 130243421213112 in words is "one hundred thirty trillion, two hundred forty-three billion, four hundred twenty-one million, two hundred thirteen thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 24 5426809217213 10853618434426 16280427651639 21707236868852 32560855303278 43414473737704 65121710606556 130243421213112