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130244112301133 = 1914092948641183
BaseRepresentation
bin11101100111010011010010…
…000011000011110001001101
3122002011012211010101001102002
4131213103102003003301031
5114032404420222114013
61141001152535442045
736301553343060425
oct3547232203036115
9562135733331362
10130244112301133
1138555243a34146
1212736221826325
135789c75907b9c
142423bc4a75485
15100ce3555e358
hex7674d20c3c4d

130244112301133 has 8 divisors (see below), whose sum is σ = 137100041222400. Its totient is φ = 123388280944128.

The previous prime is 130244112301097. The next prime is 130244112301139. The reversal of 130244112301133 is 331103211442031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130244112301133 - 216 = 130244112235597 is a prime.

It is a super-2 number, since 2×1302441123011332 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130244112301096 and 130244112301105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130244112301139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21642941 + ... + 26998242.

It is an arithmetic number, because the mean of its divisors is an integer number (17137505152800).

Almost surely, 2130244112301133 is an apocalyptic number.

It is an amenable number.

130244112301133 is a deficient number, since it is larger than the sum of its proper divisors (6855928921267).

130244112301133 is a wasteful number, since it uses less digits than its factorization.

130244112301133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48782131.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 130244112301133 its reverse (331103211442031), we get a palindrome (461347323743164).

The spelling of 130244112301133 in words is "one hundred thirty trillion, two hundred forty-four billion, one hundred twelve million, three hundred one thousand, one hundred thirty-three".

Divisors: 1 19 140929 2677651 48641183 924182477 6854953279007 130244112301133