130253999 has 2 divisors, whose sum is σ = 130254000. Its totient is φ = 130253998.

The previous prime is 130253947. The next prime is 130254001. The reversal of 130253999 is 999352031.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (999352031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130253999 - 2⁸ = 130253743 is a prime.

It is a super-2 number, since 2×130253999² = 33932208510984002, which contains 22 as substring.

Together with 130254001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130253939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65126999 + 65127000.

It is an arithmetic number, because the mean of its divisors is an integer number (65127000).

Almost surely, 2^130253999 is an apocalyptic number.

130253999 is a deficient number, since it is larger than the sum of its proper divisors (1).

130253999 is an equidigital number, since it uses as much as digits as its factorization.

130253999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 65610, while the sum is 41.

The square root of 130253999 is about 11412.8874085395. The cubic root of 130253999 is about 506.9094122381.

The spelling of 130253999 in words is "one hundred thirty million, two hundred fifty-three thousand, nine hundred ninety-nine".