1303000042 has 4 divisors (see below), whose sum is σ = 1954500066. Its totient is φ = 651500020.

The previous prime is 1303000033. The next prime is 1303000051. The reversal of 1303000042 is 2400003031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1303000033) and next prime (1303000051).

It can be written as a sum of positive squares in only one way, i.e., 693848281 + 609151761 = 26341^2 + 24681^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1302999986 and 1303000031.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325750009 + ... + 325750012.

Almost surely, 2^1303000042 is an apocalyptic number.

1303000042 is a deficient number, since it is larger than the sum of its proper divisors (651500024).

1303000042 is an equidigital number, since it uses as much as digits as its factorization.

1303000042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 651500023.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 1303000042 is about 36097.0918773244. The cubic root of 1303000042 is about 1092.2317828156.

Adding to 1303000042 its reverse (2400003031), we get a palindrome (3703003073).

The spelling of 1303000042 in words is "one billion, three hundred three million, forty-two", and thus it is an aban number.