13031110111 has 2 divisors, whose sum is σ = 13031110112. Its totient is φ = 13031110110.

The previous prime is 13031110109. The next prime is 13031110129. The reversal of 13031110111 is 11101113031.

It is a weak prime.

It is an emirp because it is prime and its reverse (11101113031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13031110111 - 2¹ = 13031110109 is a prime.

Together with 13031110109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13031110091 and 13031110100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13031113111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515555055 + 6515555056.

It is an arithmetic number, because the mean of its divisors is an integer number (6515555056).

Almost surely, 2^13031110111 is an apocalyptic number.

13031110111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031110111 is an equidigital number, since it uses as much as digits as its factorization.

13031110111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13031110111 its reverse (11101113031), we get a palindrome (24132223142).

The spelling of 13031110111 in words is "thirteen billion, thirty-one million, one hundred ten thousand, one hundred eleven".