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130312200140 = 2256515610007
BaseRepresentation
bin111100101011100110…
…1100101111111001100
3110110100200101122200222
41321113031211333030
54113334410401030
6135510430410512
712262154265563
oct1712715457714
9413320348628
10130312200140
11502a0926781
1221309360a38
13c399784745
146442b36bda
1535ca4823e5
hex1e57365fcc

130312200140 has 12 divisors (see below), whose sum is σ = 273655620336. Its totient is φ = 52124880048.

The previous prime is 130312200119. The next prime is 130312200149. The reversal of 130312200140 is 41002213031.

It is not an unprimeable number, because it can be changed into a prime (130312200149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3257804984 + ... + 3257805023.

It is an arithmetic number, because the mean of its divisors is an integer number (22804635028).

Almost surely, 2130312200140 is an apocalyptic number.

130312200140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130312200140 is an abundant number, since it is smaller than the sum of its proper divisors (143343420196).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130312200140 is a wasteful number, since it uses less digits than its factorization.

130312200140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6515610016 (or 6515610014 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 130312200140 its reverse (41002213031), we get a palindrome (171314413171).

The spelling of 130312200140 in words is "one hundred thirty billion, three hundred twelve million, two hundred thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 6515610007 13031220014 26062440028 32578050035 65156100070 130312200140