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1303200013103 = 10391254282977
BaseRepresentation
bin10010111101101100110…
…001100001101100101111
311121120210020201221221222
4102331230301201230233
5132322423200404403
62434403135013555
7163103340224552
oct22755461415457
94546706657858
101303200013103
1146275848441a
1219069b06a2bb
1395b7806bc11
144710a578699
1523d74d27338
hex12f6cc61b2f

1303200013103 has 4 divisors (see below), whose sum is σ = 1304454297120. Its totient is φ = 1301945729088.

The previous prime is 1303200013051. The next prime is 1303200013109. The reversal of 1303200013103 is 3013100023031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303200013103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303200013109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 627140450 + ... + 627142527.

It is an arithmetic number, because the mean of its divisors is an integer number (326113574280).

Almost surely, 21303200013103 is an apocalyptic number.

1303200013103 is a deficient number, since it is larger than the sum of its proper divisors (1254284017).

1303200013103 is a wasteful number, since it uses less digits than its factorization.

1303200013103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1254284016.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1303200013103 its reverse (3013100023031), we get a palindrome (4316300036134).

The spelling of 1303200013103 in words is "one trillion, three hundred three billion, two hundred million, thirteen thousand, one hundred three".

Divisors: 1 1039 1254282977 1303200013103