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1303212212021 is a prime number
BaseRepresentation
bin10010111101101101100…
…000000011111100110101
311121120211002200201201202
4102331231200003330311
5132322434311241041
62434404252302245
7163103546013116
oct22755540037465
94546732621652
101303212212021
11462764356675
121906a3171985
1395b7a750605
144710c03220d
1523d75e36a9b
hex12f6d803f35

1303212212021 has 2 divisors, whose sum is σ = 1303212212022. Its totient is φ = 1303212212020.

The previous prime is 1303212212017. The next prime is 1303212212023. The reversal of 1303212212021 is 1202122123031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 787816008100 + 515396203921 = 887590^2 + 717911^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303212212021 - 22 = 1303212212017 is a prime.

Together with 1303212212023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1303212211984 and 1303212212002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303212212023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651606106010 + 651606106011.

It is an arithmetic number, because the mean of its divisors is an integer number (651606106011).

Almost surely, 21303212212021 is an apocalyptic number.

It is an amenable number.

1303212212021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303212212021 is an equidigital number, since it uses as much as digits as its factorization.

1303212212021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1303212212021 its reverse (1202122123031), we get a palindrome (2505334335052).

The spelling of 1303212212021 in words is "one trillion, three hundred three billion, two hundred twelve million, two hundred twelve thousand, twenty-one".