130323234112110 has 384 divisors, whose sum is σ = 387623400562944. Its totient is φ = 30094755102720.

The previous prime is 130323234112081. The next prime is 130323234112133. The reversal of 130323234112110 is 11211432323031.

130323234112110 is a `hidden beast` number, since 1 + 3 + 0 + 3 + 2 + 32 + 3 + 411 + 211 + 0 = 666.

130323234112110 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 7866427047 + ... + 7866443613.

It is an arithmetic number, because the mean of its divisors is an integer number (1009435938966).

Almost surely, 2^{130323234112110} is an apocalyptic number.

130323234112110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 130323234112110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193811700281472).

130323234112110 is an abundant number, since it is smaller than the sum of its proper divisors (257300166450834).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130323234112110 is a wasteful number, since it uses less digits than its factorization.

130323234112110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17868 (or 17865 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 130323234112110 its reverse (11211432323031), we get a palindrome (141534666435141).

The spelling of 130323234112110 in words is "one hundred thirty trillion, three hundred twenty-three billion, two hundred thirty-four million, one hundred twelve thousand, one hundred ten".