Base | Representation |
---|---|
bin | 11101101000011101000100… |
… | …011010011011111011010000 |
3 | 122002102210022200002200120112 |
4 | 131220131010122123323100 |
5 | 114040204200123141334 |
6 | 1141101414401500452 |
7 | 36310356603135656 |
oct | 3550350432337320 |
9 | 562383280080515 |
10 | 130323340443344 |
11 | 38585900181024 |
12 | 12749653041728 |
13 | 5794590b612c9 |
14 | 242797d0ccdd6 |
15 | 1010020db44ce |
hex | 76874469bed0 |
130323340443344 has 10 divisors (see below), whose sum is σ = 252501472109010. Its totient is φ = 65161670221664.
The previous prime is 130323340443341. The next prime is 130323340443367. The reversal of 130323340443344 is 443344043323031.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 85792276057744 + 44531064385600 = 9262412^2 + 6673160^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130323340443341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4072604388839 + ... + 4072604388870.
It is an arithmetic number, because the mean of its divisors is an integer number (25250147210901).
Almost surely, 2130323340443344 is an apocalyptic number.
It is an amenable number.
130323340443344 is a deficient number, since it is larger than the sum of its proper divisors (122178131665666).
130323340443344 is an equidigital number, since it uses as much as digits as its factorization.
130323340443344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8145208777717 (or 8145208777711 counting only the distinct ones).
The product of its (nonzero) digits is 1492992, while the sum is 41.
Adding to 130323340443344 its reverse (443344043323031), we get a palindrome (573667383766375).
The spelling of 130323340443344 in words is "one hundred thirty trillion, three hundred twenty-three billion, three hundred forty million, four hundred forty-three thousand, three hundred forty-four".
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