Base | Representation |
---|---|
bin | 10010111101110010101… |
… | …111110000000110100111 |
3 | 11121121001020021112210022 |
4 | 102331302233300012213 |
5 | 132323124323223421 |
6 | 2434421114345355 |
7 | 163105665003203 |
oct | 22756257600647 |
9 | 4547036245708 |
10 | 1303300211111 |
11 | 4627a9aa0698 |
12 | 19070872b25b |
13 | 95b92a51892 |
14 | 471199bbb03 |
15 | 23d7da1a7ab |
hex | 12f72bf01a7 |
1303300211111 has 2 divisors, whose sum is σ = 1303300211112. Its totient is φ = 1303300211110.
The previous prime is 1303300211093. The next prime is 1303300211203. The reversal of 1303300211111 is 1111120033031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1303300211111 - 26 = 1303300211047 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1303300211111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303300211611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651650105555 + 651650105556.
It is an arithmetic number, because the mean of its divisors is an integer number (651650105556).
Almost surely, 21303300211111 is an apocalyptic number.
1303300211111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303300211111 is an equidigital number, since it uses as much as digits as its factorization.
1303300211111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1303300211111 its reverse (1111120033031), we get a palindrome (2414420244142).
The spelling of 1303300211111 in words is "one trillion, three hundred three billion, three hundred million, two hundred eleven thousand, one hundred eleven".
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