Search a number
-
+
13033101200302 = 26516550600151
BaseRepresentation
bin1011110110101000000101…
…0111100000101110101110
31201010221201020020201201001
42331222001113200232232
53202013242401402202
643415153554110514
72513416253224501
oct275520127405656
951127636221631
1013033101200302
114175341945487
121565a9b27b43a
137370296a8981
14330b3c29b138
1517904a694d87
hexbda815e0bae

13033101200302 has 4 divisors (see below), whose sum is σ = 19549651800456. Its totient is φ = 6516550600150.

The previous prime is 13033101200299. The next prime is 13033101200303. The reversal of 13033101200302 is 20300210133031.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13033101200302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13033101200303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3258275300074 + ... + 3258275300077.

It is an arithmetic number, because the mean of its divisors is an integer number (4887412950114).

Almost surely, 213033101200302 is an apocalyptic number.

13033101200302 is a deficient number, since it is larger than the sum of its proper divisors (6516550600154).

13033101200302 is an equidigital number, since it uses as much as digits as its factorization.

13033101200302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6516550600153.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13033101200302 its reverse (20300210133031), we get a palindrome (33333311333333).

The spelling of 13033101200302 in words is "thirteen trillion, thirty-three billion, one hundred one million, two hundred thousand, three hundred two".

Divisors: 1 2 6516550600151 13033101200302