130333141031 has 2 divisors, whose sum is σ = 130333141032. Its totient is φ = 130333141030.

The previous prime is 130333141027. The next prime is 130333141033. The reversal of 130333141031 is 130141333031.

It is a strong prime.

It is an emirp because it is prime and its reverse (130141333031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130333141031 - 2² = 130333141027 is a prime.

It is a super-2 number, since 2×130333141031² (a number of 23 digits) contains 22 as substring.

Together with 130333141033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130333140988 and 130333141006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130333141033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65166570515 + 65166570516.

It is an arithmetic number, because the mean of its divisors is an integer number (65166570516).

Almost surely, 2^130333141031 is an apocalyptic number.

130333141031 is a deficient number, since it is larger than the sum of its proper divisors (1).

130333141031 is an equidigital number, since it uses as much as digits as its factorization.

130333141031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 130333141031 its reverse (130141333031), we get a palindrome (260474474062).

The spelling of 130333141031 in words is "one hundred thirty billion, three hundred thirty-three million, one hundred forty-one thousand, thirty-one".