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13033997477 is a prime number
BaseRepresentation
bin11000010001110001…
…10000010010100101
31020122100202200020022
430020320300102211
5203143200404402
65553203444525
7640665102434
oct141070602245
936570680208
1013033997477
115589396246
122639086745
1312c9446357
148b909911b
1551441a2a2
hex308e304a5

13033997477 has 2 divisors, whose sum is σ = 13033997478. Its totient is φ = 13033997476.

The previous prime is 13033997447. The next prime is 13033997479. The reversal of 13033997477 is 77479933031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10793963236 + 2240034241 = 103894^2 + 47329^2 .

It is an emirp because it is prime and its reverse (77479933031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13033997477 - 218 = 13033735333 is a prime.

Together with 13033997479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13033997479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516998738 + 6516998739.

It is an arithmetic number, because the mean of its divisors is an integer number (6516998739).

Almost surely, 213033997477 is an apocalyptic number.

It is an amenable number.

13033997477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13033997477 is an equidigital number, since it uses as much as digits as its factorization.

13033997477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3000564, while the sum is 53.

The spelling of 13033997477 in words is "thirteen billion, thirty-three million, nine hundred ninety-seven thousand, four hundred seventy-seven".