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13035340143412 = 223258835035853
BaseRepresentation
bin1011110110110000011011…
…0100011001101100110100
31201011011111021012211020221
42331230012310121230310
53202032334034042122
643420204054304124
72513525611020436
oct275540664315464
951134437184227
1013035340143412
114176290753594
121566405058044
137372c54c3a92
14330cb1794656
1517912c0056c7
hexbdb06d19b34

13035340143412 has 6 divisors (see below), whose sum is σ = 22811845250978. Its totient is φ = 6517670071704.

The previous prime is 13035340143403. The next prime is 13035340143439. The reversal of 13035340143412 is 21434104353031.

It can be written as a sum of positive squares in only one way, i.e., 12110580960676 + 924759182736 = 3480026^2 + 961644^2 .

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1629417517923 + ... + 1629417517930.

Almost surely, 213035340143412 is an apocalyptic number.

It is an amenable number.

13035340143412 is a deficient number, since it is larger than the sum of its proper divisors (9776505107566).

13035340143412 is a wasteful number, since it uses less digits than its factorization.

13035340143412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3258835035857 (or 3258835035855 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 13035340143412 its reverse (21434104353031), we get a palindrome (34469444496443).

The spelling of 13035340143412 in words is "thirteen trillion, thirty-five billion, three hundred forty million, one hundred forty-three thousand, four hundred twelve".

Divisors: 1 2 4 3258835035853 6517670071706 13035340143412