Base | Representation |
---|---|
bin | 1011110110110011011010… |
… | …1000011100011101010000 |
3 | 1201011020120011122101021111 |
4 | 2331230312220130131100 |
5 | 3202041004413042334 |
6 | 43420415431503104 |
7 | 2513554521251221 |
oct | 275546650343520 |
9 | 51136504571244 |
10 | 13036142315344 |
11 | 41766625381a5 |
12 | 15665a9827a94 |
13 | 7373c2757425 |
14 | 330d4a127248 |
15 | 17917765b064 |
hex | bdb36a1c750 |
13036142315344 has 40 divisors (see below), whose sum is σ = 25271068173120. Its totient is φ = 6514577126400.
The previous prime is 13036142315323. The next prime is 13036142315347. The reversal of 13036142315344 is 44351324163031.
It is a junction number, because it is equal to n+sod(n) for n = 13036142315297 and 13036142315306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13036142315347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 336736149 + ... + 336774859.
It is an arithmetic number, because the mean of its divisors is an integer number (631776704328).
Almost surely, 213036142315344 is an apocalyptic number.
It is an amenable number.
13036142315344 is a deficient number, since it is larger than the sum of its proper divisors (12234925857776).
13036142315344 is a wasteful number, since it uses less digits than its factorization.
13036142315344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49459 (or 49453 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 13036142315344 its reverse (44351324163031), we get a palindrome (57387466478375).
The spelling of 13036142315344 in words is "thirteen trillion, thirty-six billion, one hundred forty-two million, three hundred fifteen thousand, three hundred forty-four".
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