13040112333 has 8 divisors (see below), whose sum is σ = 17398804896. Its totient is φ = 8687414000.

The previous prime is 13040112299. The next prime is 13040112343. The reversal of 13040112333 is 33321104031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13040112333 - 2⁸ = 13040112077 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040112343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1493478 + ... + 1502183.

It is an arithmetic number, because the mean of its divisors is an integer number (2174850612).

Almost surely, 2^13040112333 is an apocalyptic number.

It is an amenable number.

13040112333 is a deficient number, since it is larger than the sum of its proper divisors (4358692563).

13040112333 is a wasteful number, since it uses less digits than its factorization.

13040112333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2997115.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13040112333 its reverse (33321104031), we get a palindrome (46361216364).

The spelling of 13040112333 in words is "thirteen billion, forty million, one hundred twelve thousand, three hundred thirty-three".