Base | Representation |
---|---|
bin | 11101101001100101100001… |
… | …000110110001111001011100 |
3 | 122002201020010001012122202101 |
4 | 131221211201012301321130 |
5 | 114042443004044203202 |
6 | 1141201241440334444 |
7 | 36316112411043400 |
oct | 3551454106617134 |
9 | 562636101178671 |
10 | 130401131241052 |
11 | 3860589a042791 |
12 | 12760743014424 |
13 | 579ba0a392019 |
14 | 242b63c6b3100 |
15 | 1012075449887 |
hex | 7699611b1e5c |
130401131241052 has 72 divisors (see below), whose sum is σ = 265718975830560. Its totient is φ = 55831573768320.
The previous prime is 130401131241001. The next prime is 130401131241071. The reversal of 130401131241052 is 250142131104031.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a self number, because there is not a number n which added to its sum of digits gives 130401131241052.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2005244074 + ... + 2005309102.
It is an arithmetic number, because the mean of its divisors is an integer number (3690541330980).
Almost surely, 2130401131241052 is an apocalyptic number.
It is an amenable number.
130401131241052 is an abundant number, since it is smaller than the sum of its proper divisors (135317844589508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130401131241052 is a wasteful number, since it uses less digits than its factorization.
130401131241052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74891 (or 74882 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 130401131241052 its reverse (250142131104031), we get a palindrome (380543262345083).
The spelling of 130401131241052 in words is "one hundred thirty trillion, four hundred one billion, one hundred thirty-one million, two hundred forty-one thousand, fifty-two".
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