130401340001 has 4 divisors (see below), whose sum is σ = 130920867504. Its totient is φ = 129881812500.

The previous prime is 130401339989. The next prime is 130401340031. The reversal of 130401340001 is 100043104031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100043104031 = 13 ⋅7695623387.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130401340001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130401340031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259763375 + ... + 259763876.

It is an arithmetic number, because the mean of its divisors is an integer number (32730216876).

Almost surely, 2^130401340001 is an apocalyptic number.

It is an amenable number.

130401340001 is a deficient number, since it is larger than the sum of its proper divisors (519527503).

130401340001 is an equidigital number, since it uses as much as digits as its factorization.

130401340001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 519527502.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 130401340001 its reverse (100043104031), we get a palindrome (230444444032).

The spelling of 130401340001 in words is "one hundred thirty billion, four hundred one million, three hundred forty thousand, one".