1304020210130 has 24 divisors (see below), whose sum is σ = 2580020153676. Its totient is φ = 474189166880.

The previous prime is 1304020210121. The next prime is 1304020210151. The reversal of 1304020210130 is 310120204031.

It can be written as a sum of positive squares in 2 ways, for example, as 1275402059569 + 28618150561 = 1129337^2 + 169169^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1304020210099 and 1304020210108.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 538850117 + ... + 538852536.

Almost surely, 2^{1304020210130} is an apocalyptic number.

1304020210130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1304020210130 is a deficient number, since it is larger than the sum of its proper divisors (1275999943546).

1304020210130 is a wasteful number, since it uses less digits than its factorization.

1304020210130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1077702682 (or 1077702671 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1304020210130 its reverse (310120204031), we get a palindrome (1614140414161).

The spelling of 1304020210130 in words is "one trillion, three hundred four billion, twenty million, two hundred ten thousand, one hundred thirty".