130404332434035 has 128 divisors (see below), whose sum is σ = 250241284915200. Its totient is φ = 57241578168320.

The previous prime is 130404332434007. The next prime is 130404332434063. The reversal of 130404332434035 is 530434233404031.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (130404332434007) and next prime (130404332434063).

It is not a de Polignac number, because 130404332434035 - 2⁶ = 130404332433971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130404332433984 and 130404332434002.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 18902062 + ... + 24861548.

It is an arithmetic number, because the mean of its divisors is an integer number (1955010038400).

Almost surely, 2^{130404332434035} is an apocalyptic number.

130404332434035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130404332434035 is a deficient number, since it is larger than the sum of its proper divisors (119836952481165).

130404332434035 is a wasteful number, since it uses less digits than its factorization.

130404332434035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5959821.

The product of its (nonzero) digits is 622080, while the sum is 39.

Adding to 130404332434035 its reverse (530434233404031), we get a palindrome (660838565838066).

The spelling of 130404332434035 in words is "one hundred thirty trillion, four hundred four billion, three hundred thirty-two million, four hundred thirty-four thousand, thirty-five".