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130405431223 = 177670907719
BaseRepresentation
bin111100101110011000…
…1001111011110110111
3110110121011211021201001
41321130301033132313
54114032242244343
6135524000544131
712264365606404
oct1713461173667
9413534737631
10130405431223
1150339514661
1221334622047
13c3b2b98272
1464512852ab
1535d374b44d
hex1e5cc4f7b7

130405431223 has 4 divisors (see below), whose sum is σ = 138076338960. Its totient is φ = 122734523488.

The previous prime is 130405431197. The next prime is 130405431239. The reversal of 130405431223 is 322134504031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130405431223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130405431191 and 130405431200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130405431253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3835453843 + ... + 3835453876.

It is an arithmetic number, because the mean of its divisors is an integer number (34519084740).

Almost surely, 2130405431223 is an apocalyptic number.

130405431223 is a deficient number, since it is larger than the sum of its proper divisors (7670907737).

130405431223 is an equidigital number, since it uses as much as digits as its factorization.

130405431223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7670907736.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130405431223 its reverse (322134504031), we get a palindrome (452539935254).

The spelling of 130405431223 in words is "one hundred thirty billion, four hundred five million, four hundred thirty-one thousand, two hundred twenty-three".

Divisors: 1 17 7670907719 130405431223