Base | Representation |
---|---|
bin | 111100101110100111… |
… | …1101001000011101111 |
3 | 110110121201211011020011 |
4 | 1321131033221003233 |
5 | 4114041312302203 |
6 | 135524443434051 |
7 | 12264523420024 |
oct | 1713517510357 |
9 | 413551734204 |
10 | 130413400303 |
11 | 50342a6797a |
12 | 21337225927 |
13 | c3b47285b4 |
14 | 645235b54b |
15 | 35d42c276d |
hex | 1e5d3e90ef |
130413400303 has 4 divisors (see below), whose sum is σ = 130830056848. Its totient is φ = 129996743760.
The previous prime is 130413400289. The next prime is 130413400309. The reversal of 130413400303 is 303004314031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130413400303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130413400309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208327803 + ... + 208328428.
It is an arithmetic number, because the mean of its divisors is an integer number (32707514212).
Almost surely, 2130413400303 is an apocalyptic number.
130413400303 is a deficient number, since it is larger than the sum of its proper divisors (416656545).
130413400303 is an equidigital number, since it uses as much as digits as its factorization.
130413400303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 416656544.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 130413400303 its reverse (303004314031), we get a palindrome (433417714334).
The spelling of 130413400303 in words is "one hundred thirty billion, four hundred thirteen million, four hundred thousand, three hundred three".
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