1304201255540 has 12 divisors (see below), whose sum is σ = 2738822636676. Its totient is φ = 521680502208.

The previous prime is 1304201255519. The next prime is 1304201255557. The reversal of 1304201255540 is 455521024031.

It can be written as a sum of positive squares in 2 ways, for example, as 376342987024 + 927858268516 = 613468^2 + 963254^2 .

It is a super-2 number, since 2×1304201255540² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304201255497 and 1304201255506.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32605031369 + ... + 32605031408.

It is an arithmetic number, because the mean of its divisors is an integer number (228235219723).

Almost surely, 2^{1304201255540} is an apocalyptic number.

1304201255540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1304201255540 is an abundant number, since it is smaller than the sum of its proper divisors (1434621381136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1304201255540 is a wasteful number, since it uses less digits than its factorization.

1304201255540 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65210062786 (or 65210062784 counting only the distinct ones).

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 1304201255540 its reverse (455521024031), we get a palindrome (1759722279571).

The spelling of 1304201255540 in words is "one trillion, three hundred four billion, two hundred one million, two hundred fifty-five thousand, five hundred forty".