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130424111 is a prime number
BaseRepresentation
bin1111100011000…
…01110100101111
3100002102020020122
413301201310233
5231342032421
620535235155
73142405136
oct761416457
9302366218
10130424111
1167691624
1237818abb
132103683c
141347091d
15b6b42ab
hex7c61d2f

130424111 has 2 divisors, whose sum is σ = 130424112. Its totient is φ = 130424110.

The previous prime is 130424087. The next prime is 130424123. The reversal of 130424111 is 111424031.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (111424031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130424111 - 226 = 63315247 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130424111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130424131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65212055 + 65212056.

It is an arithmetic number, because the mean of its divisors is an integer number (65212056).

Almost surely, 2130424111 is an apocalyptic number.

130424111 is a deficient number, since it is larger than the sum of its proper divisors (1).

130424111 is an equidigital number, since it uses as much as digits as its factorization.

130424111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 130424111 is about 11420.3376044669. The cubic root of 130424111 is about 507.1299911643.

Adding to 130424111 its reverse (111424031), we get a palindrome (241848142).

The spelling of 130424111 in words is "one hundred thirty million, four hundred twenty-four thousand, one hundred eleven".