Base | Representation |
---|---|
bin | 111100101110111111… |
… | …0011101010010111010 |
3 | 110110122120220200001102 |
4 | 1321131332131102322 |
5 | 4114102433013030 |
6 | 135530002451402 |
7 | 12265032633122 |
oct | 1713576352272 |
9 | 413576820042 |
10 | 130425672890 |
11 | 5034998a507 |
12 | 2133b363b62 |
13 | c3b7134696 |
14 | 6453c33c82 |
15 | 35d53e8c45 |
hex | 1e5df9d4ba |
130425672890 has 64 divisors (see below), whose sum is σ = 247245073920. Its totient is φ = 49441117440.
The previous prime is 130425672863. The next prime is 130425672917. The reversal of 130425672890 is 98276524031.
It is an interprime number because it is at equal distance from previous prime (130425672863) and next prime (130425672917).
It is a super-3 number, since 3×1304256728903 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12958460 + ... + 12968520.
It is an arithmetic number, because the mean of its divisors is an integer number (3863204280).
It is a 1-persistent number, because it is pandigital, but 2⋅130425672890 = 260851345780 is not.
Almost surely, 2130425672890 is an apocalyptic number.
130425672890 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130425672890 is a deficient number, since it is larger than the sum of its proper divisors (116819401030).
130425672890 is a wasteful number, since it uses less digits than its factorization.
130425672890 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10607.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 130425672890 in words is "one hundred thirty billion, four hundred twenty-five million, six hundred seventy-two thousand, eight hundred ninety".
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